x=3x^2-18x+26

Solution for x=3x^2-18x+26 equation:

x=3x^2-18x+26

We move all terms to the left:

x-(3x^2-18x+26)=0

We get rid of parentheses

-3x^2+x+18x-26=0

We add all the numbers together, and all the variables

-3x^2+19x-26=0

a = -3; b = 19; c = -26;
Δ = b2-4ac
Δ = 192-4·(-3)·(-26)
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-7}{2*-3}=\frac{-26}{-6}
=4+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+7}{2*-3}=\frac{-12}{-6}
=+2
$